Std.Option.mapPresent
1 declaration
fn
mapPresent: &Array[A] -> fn(A) -> Option[B] -> Array[B]This is a callable function.
What it does
Every element transformed, keeping only the results that are present.
One pass rather than a map followed by a filter, which is why it exists.
Read the signature
- The text after the name is the type checked by Pudu.
- Read arrows from left to right: inputs come first, and the final type is returned.
- & borrows a value for this call instead of moving or copying it.
- Names inside [ ] are type arguments, such as the item type held by a collection.
- Option holds Some(value) or None when no value is available.
