Results for “Std.Ui.Screen.handle”
1 matching declarations
Use module:Std.List, kind:fn, or is:exact. Put a Pudu type after ::.
- Std.Ui.Screen.handle
&Std.Ui.Screen.Screen[S] -> Std.Ui.Screen.Input -> Result[Std.Ui.Screen.Screen[S], Std.Ui.Screen.ScreenError]The screen after one input.
